2/5x^2=6

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Solution for 2/5x^2=6 equation:



2/5x^2=6
We move all terms to the left:
2/5x^2-(6)=0
Domain of the equation: 5x^2!=0
x^2!=0/5
x^2!=√0
x!=0
x∈R
We multiply all the terms by the denominator
-6*5x^2+2=0
Wy multiply elements
-30x^2+2=0
a = -30; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-30)·2
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*-30}=\frac{0-4\sqrt{15}}{-60} =-\frac{4\sqrt{15}}{-60} =-\frac{\sqrt{15}}{-15} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*-30}=\frac{0+4\sqrt{15}}{-60} =\frac{4\sqrt{15}}{-60} =\frac{\sqrt{15}}{-15} $

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